(a-4)(a+5)=(a+2)(a+3)

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Solution for (a-4)(a+5)=(a+2)(a+3) equation: 



(a-4)(a+5)=(a+2)(a+3)

We move all terms to the left:

(a-4)(a+5)-((a+2)(a+3))=0

We multiply parentheses ..

(+a^2+5a-4a-20)-((a+2)(a+3))=0



We calculate terms in parentheses: -((a+2)(a+3)), so:

(a+2)(a+3)

We multiply parentheses ..

(+a^2+3a+2a+6)

We get rid of parentheses

a^2+3a+2a+6

We add all the numbers together, and all the variables

a^2+5a+6

Back to the equation:

-(a^2+5a+6)



We get rid of parentheses

a^2-a^2+5a-4a-5a-20-6=0

We add all the numbers together, and all the variables

-4a-26=0

We move all terms containing a to the left, all other terms to the right

-4a=26

a=26/-4

a=-6+1/2

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