(a-4)/6=(2a+4)/3

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Solution for (a-4)/6=(2a+4)/3 equation: 



(a-4)/6=(2a+4)/3

We move all terms to the left:

(a-4)/6-((2a+4)/3)=0

We calculate fractions


a/()+(-((2a+4)*6)/()=0



We calculate terms in parentheses: +(-((2a+4)*6)/(), so:

-((2a+4)*6)/(

We multiply all the terms by the denominator


-((2a+4)*6)



We calculate terms in parentheses: -((2a+4)*6), so:

(2a+4)*6

We multiply parentheses

12a+24

Back to the equation:

-(12a+24)



We get rid of parentheses

-12a-24

Back to the equation:

+(-12a-24)



We get rid of parentheses

a/()-12a-24=0

We multiply all the terms by the denominator


a-12a*()-24*()=0

We add all the numbers together, and all the variables

a-12a*()=0

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