(a-x)/(8-3x)=(a+1)/7

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Solution for (a-x)/(8-3x)=(a+1)/7 equation:


D( x )

8-(3*x) = 0

8-(3*x) = 0

8-(3*x) = 0

8-3*x = 0

8-3*x = 0 // - 8

-3*x = -8 // : -3

x = -8/(-3)

x = 8/3

x in (-oo:8/3) U (8/3:+oo)

(a-x)/(8-(3*x)) = (a+1)/7 // - (a+1)/7

(a-x)/(8-(3*x))-((a+1)/7) = 0

(a-x)/(8-3*x)-((a+1)/7) = 0

(a-x)/(8-3*x)+(-1*(a+1))/7 = 0

(7*(a-x))/(7*(8-3*x))+(-1*(a+1)*(8-3*x))/(7*(8-3*x)) = 0

7*(a-x)-1*(a+1)*(8-3*x) = 0

3*a*x-a-4*x-8 = 0

(3*a*x-a-4*x-8)/(7*(8-3*x)) = 0

(3*a*x-a-4*x-8)/(7*(8-3*x)) = 0 // * 7*(8-3*x)

3*a*x-a-4*x-8 = 0

-a-4*x-8 = 0 // + -a-8

-4*x = -(-a-8) // : -4

x = (-(-a-8))/(-4)

x = (a+8)/(-4)

x = (a+8)/(-4)

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