(a/10)+8=(7/2)

Solution for (a/10)+8=(7/2) equation:

(a/10)+8=(7/2)

We move all terms to the left:

(a/10)+8-((7/2))=0

We add all the numbers together, and all the variables

(+a/10)+8-((+7/2))=0

We get rid of parentheses

a/10+8-((+7/2))=0

We calculate fractions


2a^2/()+8+()/()=0

We add all the numbers together, and all the variables

2a^2/()+9=0

We multiply all the terms by the denominator


2a^2+9*()=0

We add all the numbers together, and all the variables

2a^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{4}=0$