(a/20)=(20/(a-19))

Solution for (a/20)=(20/(a-19)) equation:

(a/20)=(20/(a-19))

We move all terms to the left:

(a/20)-((20/(a-19)))=0


Domain of the equation: (a-19)))!=0

a∈R


We add all the numbers together, and all the variables

(+a/20)-((20/(a-19)))=0

We get rid of parentheses

a/20-((20/(a-19)))=0

We calculate fractions


(-18a^2)/20a+()/20a=0

We multiply all the terms by the denominator


(-18a^2)+()=0

We add all the numbers together, and all the variables

(-18a^2)=0

We get rid of parentheses

-18a^2=0

a = -18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-18)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{-36}=0$