(a/3)+(a/2)+a+2a+3a=41

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Solution for (a/3)+(a/2)+a+2a+3a=41 equation: 



(a/3)+(a/2)+a+2a+3a=41

We move all terms to the left:

(a/3)+(a/2)+a+2a+3a-(41)=0

We add all the numbers together, and all the variables

(+a/3)+(+a/2)+a+2a+3a-41=0

We add all the numbers together, and all the variables

6a+(+a/3)+(+a/2)-41=0

We get rid of parentheses

6a+a/3+a/2-41=0

We calculate fractions

There is no solution for this equation

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