(a/5)(2a-10)=0

Solution for (a/5)(2a-10)=0 equation:

(a/5)(2a-10)=0


Domain of the equation: 5)(2a-10)!=0

a∈R


We add all the numbers together, and all the variables

(+a/5)(2a-10)=0

We multiply parentheses ..

(+2a^2-10a)=0

We get rid of parentheses

2a^2-10a=0

a = 2; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·2·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*2}=\frac{0}{4}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*2}=\frac{20}{4}
=5
$