(a2+2a)=(6a-18)

Solution for (a2+2a)=(6a-18) equation:

(a2+2a)=(6a-18)

We move all terms to the left:

(a2+2a)-((6a-18))=0

We add all the numbers together, and all the variables

(+a^2+2a)-((6a-18))=0

We get rid of parentheses

a^2+2a-((6a-18))=0


We calculate terms in parentheses: -((6a-18)), so:

(6a-18)

We get rid of parentheses

6a-18

Back to the equation:

-(6a-18)


We get rid of parentheses

a^2+2a-6a+18=0

We add all the numbers together, and all the variables

a^2-4a+18=0

a = 1; b = -4; c = +18;
Δ = b2-4ac
Δ = -42-4·1·18
Δ = -56
Delta is less than zero, so there is no solution for the equation