(ax-12)(4x-a)=0

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Solution for (ax-12)(4x-a)=0 equation: 


Simplifying
(ax + -12)(4x + -1a) = 0

Reorder the terms:
(-12 + ax)(4x + -1a) = 0

Reorder the terms:
(-12 + ax)(-1a + 4x) = 0

Multiply (-12 + ax) * (-1a + 4x)
(-12(-1a + 4x) + ax(-1a + 4x)) = 0
((-1a * -12 + 4x * -12) + ax(-1a + 4x)) = 0
((12a + -48x) + ax(-1a + 4x)) = 0
(12a + -48x + (-1a * ax + 4x * ax)) = 0

Reorder the terms:
(12a + -48x + (4ax2 + -1a2x)) = 0
(12a + -48x + (4ax2 + -1a2x)) = 0

Reorder the terms:
(12a + 4ax2 + -1a2x + -48x) = 0
(12a + 4ax2 + -1a2x + -48x) = 0

Solving
12a + 4ax2 + -1a2x + -48x = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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