(b+1)(2b+3)=0

Solution for (b+1)(2b+3)=0 equation:

Simplifying
(b + 1)(2b + 3) = 0

Reorder the terms:
(1 + b)(2b + 3) = 0

Reorder the terms:
(1 + b)(3 + 2b) = 0

Multiply (1 + b) * (3 + 2b)
(1(3 + 2b) + b(3 + 2b)) = 0
((3 * 1 + 2b * 1) + b(3 + 2b)) = 0
((3 + 2b) + b(3 + 2b)) = 0
(3 + 2b + (3 * b + 2b * b)) = 0
(3 + 2b + (3b + 2b2)) = 0

Combine like terms: 2b + 3b = 5b
(3 + 5b + 2b2) = 0

Solving
3 + 5b + 2b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(3 + 2b)(1 + b) = 0

Subproblem 1
Set the factor '(3 + 2b)' equal to zero and attempt to solve:

Simplifying
3 + 2b = 0

Solving
3 + 2b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2b = 0 + -3
2b = 0 + -3

Combine like terms: 0 + -3 = -3
2b = -3

Divide each side by '2'.
b = -1.5

Simplifying
b = -1.5
Subproblem 2
Set the factor '(1 + b)' equal to zero and attempt to solve:

Simplifying
1 + b = 0

Solving
1 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + b = 0 + -1
b = 0 + -1

Combine like terms: 0 + -1 = -1
b = -1

Simplifying
b = -1
Solution
b = {-1.5, -1}