(b+1)(b+1)(b+1)=

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Solution for (b+1)(b+1)(b+1)= equation:


Simplifying
(b + 1)(b + 1)(b + 1) = 0

Reorder the terms:
(1 + b)(b + 1)(b + 1) = 0

Reorder the terms:
(1 + b)(1 + b)(b + 1) = 0

Reorder the terms:
(1 + b)(1 + b)(1 + b) = 0

Multiply (1 + b) * (1 + b)
(1(1 + b) + b(1 + b))(1 + b) = 0
((1 * 1 + b * 1) + b(1 + b))(1 + b) = 0
((1 + 1b) + b(1 + b))(1 + b) = 0
(1 + 1b + (1 * b + b * b))(1 + b) = 0
(1 + 1b + (1b + b2))(1 + b) = 0

Combine like terms: 1b + 1b = 2b
(1 + 2b + b2)(1 + b) = 0

Multiply (1 + 2b + b2) * (1 + b)
(1(1 + b) + 2b * (1 + b) + b2(1 + b)) = 0
((1 * 1 + b * 1) + 2b * (1 + b) + b2(1 + b)) = 0
((1 + 1b) + 2b * (1 + b) + b2(1 + b)) = 0
(1 + 1b + (1 * 2b + b * 2b) + b2(1 + b)) = 0
(1 + 1b + (2b + 2b2) + b2(1 + b)) = 0
(1 + 1b + 2b + 2b2 + (1 * b2 + b * b2)) = 0
(1 + 1b + 2b + 2b2 + (1b2 + b3)) = 0

Combine like terms: 1b + 2b = 3b
(1 + 3b + 2b2 + 1b2 + b3) = 0

Combine like terms: 2b2 + 1b2 = 3b2
(1 + 3b + 3b2 + b3) = 0

Solving
1 + 3b + 3b2 + b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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