(b+1)(b+49)=0

Solution for (b+1)(b+49)=0 equation:

Simplifying
(b + 1)(b + 49) = 0

Reorder the terms:
(1 + b)(b + 49) = 0

Reorder the terms:
(1 + b)(49 + b) = 0

Multiply (1 + b) * (49 + b)
(1(49 + b) + b(49 + b)) = 0
((49 * 1 + b * 1) + b(49 + b)) = 0
((49 + 1b) + b(49 + b)) = 0
(49 + 1b + (49 * b + b * b)) = 0
(49 + 1b + (49b + b2)) = 0

Combine like terms: 1b + 49b = 50b
(49 + 50b + b2) = 0

Solving
49 + 50b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(49 + b)(1 + b) = 0

Subproblem 1
Set the factor '(49 + b)' equal to zero and attempt to solve:

Simplifying
49 + b = 0

Solving
49 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-49' to each side of the equation.
49 + -49 + b = 0 + -49

Combine like terms: 49 + -49 = 0
0 + b = 0 + -49
b = 0 + -49

Combine like terms: 0 + -49 = -49
b = -49

Simplifying
b = -49
Subproblem 2
Set the factor '(1 + b)' equal to zero and attempt to solve:

Simplifying
1 + b = 0

Solving
1 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + b = 0 + -1
b = 0 + -1

Combine like terms: 0 + -1 = -1
b = -1

Simplifying
b = -1
Solution
b = {-49, -1}