(b+1)(b-1)=0

Solution for (b+1)(b-1)=0 equation:

Simplifying
(b + 1)(b + -1) = 0

Reorder the terms:
(1 + b)(b + -1) = 0

Reorder the terms:
(1 + b)(-1 + b) = 0

Multiply (1 + b) * (-1 + b)
(1(-1 + b) + b(-1 + b)) = 0
((-1 * 1 + b * 1) + b(-1 + b)) = 0
((-1 + 1b) + b(-1 + b)) = 0
(-1 + 1b + (-1 * b + b * b)) = 0
(-1 + 1b + (-1b + b2)) = 0

Combine like terms: 1b + -1b = 0
(-1 + 0 + b2) = 0
(-1 + b2) = 0

Solving
-1 + b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + b2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + b2 = 0 + 1
b2 = 0 + 1

Combine like terms: 0 + 1 = 1
b2 = 1

Simplifying
b2 = 1

Take the square root of each side:
b = {-1, 1}