(b+1)(b-1)=35

Solution for (b+1)(b-1)=35 equation:

Simplifying
(b + 1)(b + -1) = 35

Reorder the terms:
(1 + b)(b + -1) = 35

Reorder the terms:
(1 + b)(-1 + b) = 35

Multiply (1 + b) * (-1 + b)
(1(-1 + b) + b(-1 + b)) = 35
((-1 * 1 + b * 1) + b(-1 + b)) = 35
((-1 + 1b) + b(-1 + b)) = 35
(-1 + 1b + (-1 * b + b * b)) = 35
(-1 + 1b + (-1b + b2)) = 35

Combine like terms: 1b + -1b = 0
(-1 + 0 + b2) = 35
(-1 + b2) = 35

Solving
-1 + b2 = 35

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + b2 = 35 + 1

Combine like terms: -1 + 1 = 0
0 + b2 = 35 + 1
b2 = 35 + 1

Combine like terms: 35 + 1 = 36
b2 = 36

Simplifying
b2 = 36

Take the square root of each side:
b = {-6, 6}