(b+1)+9=2(3b-4)+b

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Solution for (b+1)+9=2(3b-4)+b equation:


Simplifying
(b + 1) + 9 = 2(3b + -4) + b

Reorder the terms:
(1 + b) + 9 = 2(3b + -4) + b

Remove parenthesis around (1 + b)
1 + b + 9 = 2(3b + -4) + b

Reorder the terms:
1 + 9 + b = 2(3b + -4) + b

Combine like terms: 1 + 9 = 10
10 + b = 2(3b + -4) + b

Reorder the terms:
10 + b = 2(-4 + 3b) + b
10 + b = (-4 * 2 + 3b * 2) + b
10 + b = (-8 + 6b) + b

Combine like terms: 6b + b = 7b
10 + b = -8 + 7b

Solving
10 + b = -8 + 7b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-7b' to each side of the equation.
10 + b + -7b = -8 + 7b + -7b

Combine like terms: b + -7b = -6b
10 + -6b = -8 + 7b + -7b

Combine like terms: 7b + -7b = 0
10 + -6b = -8 + 0
10 + -6b = -8

Add '-10' to each side of the equation.
10 + -10 + -6b = -8 + -10

Combine like terms: 10 + -10 = 0
0 + -6b = -8 + -10
-6b = -8 + -10

Combine like terms: -8 + -10 = -18
-6b = -18

Divide each side by '-6'.
b = 3

Simplifying
b = 3

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