(b+10)+(3b)+(b+10)=180

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Solution for (b+10)+(3b)+(b+10)=180 equation: 



(b+10)+(3b)+(b+10)=180

We move all terms to the left:

(b+10)+(3b)+(b+10)-(180)=0

We add all the numbers together, and all the variables

3b+(b+10)+(b+10)-180=0

We get rid of parentheses

3b+b+b+10+10-180=0

We add all the numbers together, and all the variables

5b-160=0

We move all terms containing b to the left, all other terms to the right

5b=160

b=160/5

b=32

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