(b+2)(b+4)=0

Solution for (b+2)(b+4)=0 equation:

Simplifying
(b + 2)(b + 4) = 0

Reorder the terms:
(2 + b)(b + 4) = 0

Reorder the terms:
(2 + b)(4 + b) = 0

Multiply (2 + b) * (4 + b)
(2(4 + b) + b(4 + b)) = 0
((4 * 2 + b * 2) + b(4 + b)) = 0
((8 + 2b) + b(4 + b)) = 0
(8 + 2b + (4 * b + b * b)) = 0
(8 + 2b + (4b + b2)) = 0

Combine like terms: 2b + 4b = 6b
(8 + 6b + b2) = 0

Solving
8 + 6b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(4 + b)(2 + b) = 0

Subproblem 1
Set the factor '(4 + b)' equal to zero and attempt to solve:

Simplifying
4 + b = 0

Solving
4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + b = 0 + -4
b = 0 + -4

Combine like terms: 0 + -4 = -4
b = -4

Simplifying
b = -4
Subproblem 2
Set the factor '(2 + b)' equal to zero and attempt to solve:

Simplifying
2 + b = 0

Solving
2 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + b = 0 + -2
b = 0 + -2

Combine like terms: 0 + -2 = -2
b = -2

Simplifying
b = -2
Solution
b = {-4, -2}