(b+2)(b-1)=

Solution for (b+2)(b-1)= equation:

Simplifying
(b + 2)(b + -1) = 0

Reorder the terms:
(2 + b)(b + -1) = 0

Reorder the terms:
(2 + b)(-1 + b) = 0

Multiply (2 + b) * (-1 + b)
(2(-1 + b) + b(-1 + b)) = 0
((-1 * 2 + b * 2) + b(-1 + b)) = 0
((-2 + 2b) + b(-1 + b)) = 0
(-2 + 2b + (-1 * b + b * b)) = 0
(-2 + 2b + (-1b + b2)) = 0

Combine like terms: 2b + -1b = 1b
(-2 + 1b + b2) = 0

Solving
-2 + 1b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-2 + -1b)(1 + -1b) = 0

Subproblem 1
Set the factor '(-2 + -1b)' equal to zero and attempt to solve:

Simplifying
-2 + -1b = 0

Solving
-2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1b = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1b = 0 + 2
-1b = 0 + 2

Combine like terms: 0 + 2 = 2
-1b = 2

Divide each side by '-1'.
b = -2

Simplifying
b = -2
Subproblem 2
Set the factor '(1 + -1b)' equal to zero and attempt to solve:

Simplifying
1 + -1b = 0

Solving
1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1b = 0 + -1
-1b = 0 + -1

Combine like terms: 0 + -1 = -1
-1b = -1

Divide each side by '-1'.
b = 1

Simplifying
b = 1
Solution
b = {-2, 1}