(b+2)(b-2)=

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Solution for (b+2)(b-2)= equation:


Simplifying
(b + 2)(b + -2) = 0

Reorder the terms:
(2 + b)(b + -2) = 0

Reorder the terms:
(2 + b)(-2 + b) = 0

Multiply (2 + b) * (-2 + b)
(2(-2 + b) + b(-2 + b)) = 0
((-2 * 2 + b * 2) + b(-2 + b)) = 0
((-4 + 2b) + b(-2 + b)) = 0
(-4 + 2b + (-2 * b + b * b)) = 0
(-4 + 2b + (-2b + b2)) = 0

Combine like terms: 2b + -2b = 0
(-4 + 0 + b2) = 0
(-4 + b2) = 0

Solving
-4 + b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + b2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + b2 = 0 + 4
b2 = 0 + 4

Combine like terms: 0 + 4 = 4
b2 = 4

Simplifying
b2 = 4

Take the square root of each side:
b = {-2, 2}

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