(b+2)(b-5)=0

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Solution for (b+2)(b-5)=0 equation:


Simplifying
(b + 2)(b + -5) = 0

Reorder the terms:
(2 + b)(b + -5) = 0

Reorder the terms:
(2 + b)(-5 + b) = 0

Multiply (2 + b) * (-5 + b)
(2(-5 + b) + b(-5 + b)) = 0
((-5 * 2 + b * 2) + b(-5 + b)) = 0
((-10 + 2b) + b(-5 + b)) = 0
(-10 + 2b + (-5 * b + b * b)) = 0
(-10 + 2b + (-5b + b2)) = 0

Combine like terms: 2b + -5b = -3b
(-10 + -3b + b2) = 0

Solving
-10 + -3b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-2 + -1b)(5 + -1b) = 0

Subproblem 1

Set the factor '(-2 + -1b)' equal to zero and attempt to solve: Simplifying -2 + -1b = 0 Solving -2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1b = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1b = 0 + 2 -1b = 0 + 2 Combine like terms: 0 + 2 = 2 -1b = 2 Divide each side by '-1'. b = -2 Simplifying b = -2

Subproblem 2

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Solution

b = {-2, 5}

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