(b+2)*(b-9)=

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Solution for (b+2)*(b-9)= equation:


Simplifying
(b + 2)(b + -9) = 0

Reorder the terms:
(2 + b)(b + -9) = 0

Reorder the terms:
(2 + b)(-9 + b) = 0

Multiply (2 + b) * (-9 + b)
(2(-9 + b) + b(-9 + b)) = 0
((-9 * 2 + b * 2) + b(-9 + b)) = 0
((-18 + 2b) + b(-9 + b)) = 0
(-18 + 2b + (-9 * b + b * b)) = 0
(-18 + 2b + (-9b + b2)) = 0

Combine like terms: 2b + -9b = -7b
(-18 + -7b + b2) = 0

Solving
-18 + -7b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-2 + -1b)(9 + -1b) = 0

Subproblem 1

Set the factor '(-2 + -1b)' equal to zero and attempt to solve: Simplifying -2 + -1b = 0 Solving -2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1b = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1b = 0 + 2 -1b = 0 + 2 Combine like terms: 0 + 2 = 2 -1b = 2 Divide each side by '-1'. b = -2 Simplifying b = -2

Subproblem 2

Set the factor '(9 + -1b)' equal to zero and attempt to solve: Simplifying 9 + -1b = 0 Solving 9 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1b = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1b = 0 + -9 -1b = 0 + -9 Combine like terms: 0 + -9 = -9 -1b = -9 Divide each side by '-1'. b = 9 Simplifying b = 9

Solution

b = {-2, 9}

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