(b+2)-5(2b-3)=3

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Solution for (b+2)-5(2b-3)=3 equation: 



(b+2)-5(2b-3)=3

We move all terms to the left:

(b+2)-5(2b-3)-(3)=0

We multiply parentheses

(b+2)-10b+15-3=0

We get rid of parentheses

b-10b+2+15-3=0

We add all the numbers together, and all the variables

-9b+14=0

We move all terms containing b to the left, all other terms to the right

-9b=-14

b=-14/-9

b=1+5/9

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