(b+20)(b-25)=0

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Solution for (b+20)(b-25)=0 equation:


Simplifying
(b + 20)(b + -25) = 0

Reorder the terms:
(20 + b)(b + -25) = 0

Reorder the terms:
(20 + b)(-25 + b) = 0

Multiply (20 + b) * (-25 + b)
(20(-25 + b) + b(-25 + b)) = 0
((-25 * 20 + b * 20) + b(-25 + b)) = 0
((-500 + 20b) + b(-25 + b)) = 0
(-500 + 20b + (-25 * b + b * b)) = 0
(-500 + 20b + (-25b + b2)) = 0

Combine like terms: 20b + -25b = -5b
(-500 + -5b + b2) = 0

Solving
-500 + -5b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-20 + -1b)(25 + -1b) = 0

Subproblem 1

Set the factor '(-20 + -1b)' equal to zero and attempt to solve: Simplifying -20 + -1b = 0 Solving -20 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '20' to each side of the equation. -20 + 20 + -1b = 0 + 20 Combine like terms: -20 + 20 = 0 0 + -1b = 0 + 20 -1b = 0 + 20 Combine like terms: 0 + 20 = 20 -1b = 20 Divide each side by '-1'. b = -20 Simplifying b = -20

Subproblem 2

Set the factor '(25 + -1b)' equal to zero and attempt to solve: Simplifying 25 + -1b = 0 Solving 25 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-25' to each side of the equation. 25 + -25 + -1b = 0 + -25 Combine like terms: 25 + -25 = 0 0 + -1b = 0 + -25 -1b = 0 + -25 Combine like terms: 0 + -25 = -25 -1b = -25 Divide each side by '-1'. b = 25 Simplifying b = 25

Solution

b = {-20, 25}

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