(b+24)(b-28)=0

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Solution for (b+24)(b-28)=0 equation:


Simplifying
(b + 24)(b + -28) = 0

Reorder the terms:
(24 + b)(b + -28) = 0

Reorder the terms:
(24 + b)(-28 + b) = 0

Multiply (24 + b) * (-28 + b)
(24(-28 + b) + b(-28 + b)) = 0
((-28 * 24 + b * 24) + b(-28 + b)) = 0
((-672 + 24b) + b(-28 + b)) = 0
(-672 + 24b + (-28 * b + b * b)) = 0
(-672 + 24b + (-28b + b2)) = 0

Combine like terms: 24b + -28b = -4b
(-672 + -4b + b2) = 0

Solving
-672 + -4b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-24 + -1b)(28 + -1b) = 0

Subproblem 1

Set the factor '(-24 + -1b)' equal to zero and attempt to solve: Simplifying -24 + -1b = 0 Solving -24 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '24' to each side of the equation. -24 + 24 + -1b = 0 + 24 Combine like terms: -24 + 24 = 0 0 + -1b = 0 + 24 -1b = 0 + 24 Combine like terms: 0 + 24 = 24 -1b = 24 Divide each side by '-1'. b = -24 Simplifying b = -24

Subproblem 2

Set the factor '(28 + -1b)' equal to zero and attempt to solve: Simplifying 28 + -1b = 0 Solving 28 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-28' to each side of the equation. 28 + -28 + -1b = 0 + -28 Combine like terms: 28 + -28 = 0 0 + -1b = 0 + -28 -1b = 0 + -28 Combine like terms: 0 + -28 = -28 -1b = -28 Divide each side by '-1'. b = 28 Simplifying b = 28

Solution

b = {-24, 28}

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