(b+3)(b+5)=0

Solution for (b+3)(b+5)=0 equation:

Simplifying
(b + 3)(b + 5) = 0

Reorder the terms:
(3 + b)(b + 5) = 0

Reorder the terms:
(3 + b)(5 + b) = 0

Multiply (3 + b) * (5 + b)
(3(5 + b) + b(5 + b)) = 0
((5 * 3 + b * 3) + b(5 + b)) = 0
((15 + 3b) + b(5 + b)) = 0
(15 + 3b + (5 * b + b * b)) = 0
(15 + 3b + (5b + b2)) = 0

Combine like terms: 3b + 5b = 8b
(15 + 8b + b2) = 0

Solving
15 + 8b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(5 + b)(3 + b) = 0

Subproblem 1
Set the factor '(5 + b)' equal to zero and attempt to solve:

Simplifying
5 + b = 0

Solving
5 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + b = 0 + -5
b = 0 + -5

Combine like terms: 0 + -5 = -5
b = -5

Simplifying
b = -5
Subproblem 2
Set the factor '(3 + b)' equal to zero and attempt to solve:

Simplifying
3 + b = 0

Solving
3 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + b = 0 + -3
b = 0 + -3

Combine like terms: 0 + -3 = -3
b = -3

Simplifying
b = -3
Solution
b = {-5, -3}