(b+3)(b-3)=

Solution for (b+3)(b-3)= equation:

Simplifying
(b + 3)(b + -3) = 0

Reorder the terms:
(3 + b)(b + -3) = 0

Reorder the terms:
(3 + b)(-3 + b) = 0

Multiply (3 + b) * (-3 + b)
(3(-3 + b) + b(-3 + b)) = 0
((-3 * 3 + b * 3) + b(-3 + b)) = 0
((-9 + 3b) + b(-3 + b)) = 0
(-9 + 3b + (-3 * b + b * b)) = 0
(-9 + 3b + (-3b + b2)) = 0

Combine like terms: 3b + -3b = 0
(-9 + 0 + b2) = 0
(-9 + b2) = 0

Solving
-9 + b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + b2 = 0 + 9

Combine like terms: -9 + 9 = 0
0 + b2 = 0 + 9
b2 = 0 + 9

Combine like terms: 0 + 9 = 9
b2 = 9

Simplifying
b2 = 9

Take the square root of each side:
b = {-3, 3}