(b+3)+(b-2)+b=19

Solution for (b+3)+(b-2)+b=19 equation:

Simplifying
(b + 3) + (b + -2) + b = 19

Reorder the terms:
(3 + b) + (b + -2) + b = 19

Remove parenthesis around (3 + b)
3 + b + (b + -2) + b = 19

Reorder the terms:
3 + b + (-2 + b) + b = 19

Remove parenthesis around (-2 + b)
3 + b + -2 + b + b = 19

Reorder the terms:
3 + -2 + b + b + b = 19

Combine like terms: 3 + -2 = 1
1 + b + b + b = 19

Combine like terms: b + b = 2b
1 + 2b + b = 19

Combine like terms: 2b + b = 3b
1 + 3b = 19

Solving
1 + 3b = 19

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 3b = 19 + -1

Combine like terms: 1 + -1 = 0
0 + 3b = 19 + -1
3b = 19 + -1

Combine like terms: 19 + -1 = 18
3b = 18

Divide each side by '3'.
b = 6

Simplifying
b = 6