(b+3)/5=(3b+3(

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Solution for (b+3)/5=(3b+3( equation: 



(b+3)/5=(3b+3(

We move all terms to the left:

(b+3)/5-((3b+3()=0

We multiply all the terms by the denominator


(b+3)-(((3b+3())*5=0

We get rid of parentheses

b-(((3b+3())*5+3=0

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