(b+3)3=(b-3)4

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Solution for (b+3)3=(b-3)4 equation:


Simplifying
(b + 3) * 3 = (b + -3) * 4

Reorder the terms:
(3 + b) * 3 = (b + -3) * 4

Reorder the terms for easier multiplication:
3(3 + b) = (b + -3) * 4
(3 * 3 + b * 3) = (b + -3) * 4
(9 + 3b) = (b + -3) * 4

Reorder the terms:
9 + 3b = (-3 + b) * 4

Reorder the terms for easier multiplication:
9 + 3b = 4(-3 + b)
9 + 3b = (-3 * 4 + b * 4)
9 + 3b = (-12 + 4b)

Solving
9 + 3b = -12 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
9 + 3b + -4b = -12 + 4b + -4b

Combine like terms: 3b + -4b = -1b
9 + -1b = -12 + 4b + -4b

Combine like terms: 4b + -4b = 0
9 + -1b = -12 + 0
9 + -1b = -12

Add '-9' to each side of the equation.
9 + -9 + -1b = -12 + -9

Combine like terms: 9 + -9 = 0
0 + -1b = -12 + -9
-1b = -12 + -9

Combine like terms: -12 + -9 = -21
-1b = -21

Divide each side by '-1'.
b = 21

Simplifying
b = 21

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