(b+4)(b-2)=

Solution for (b+4)(b-2)= equation:

Simplifying
(b + 4)(b + -2) = 0

Reorder the terms:
(4 + b)(b + -2) = 0

Reorder the terms:
(4 + b)(-2 + b) = 0

Multiply (4 + b) * (-2 + b)
(4(-2 + b) + b(-2 + b)) = 0
((-2 * 4 + b * 4) + b(-2 + b)) = 0
((-8 + 4b) + b(-2 + b)) = 0
(-8 + 4b + (-2 * b + b * b)) = 0
(-8 + 4b + (-2b + b2)) = 0

Combine like terms: 4b + -2b = 2b
(-8 + 2b + b2) = 0

Solving
-8 + 2b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-4 + -1b)(2 + -1b) = 0

Subproblem 1
Set the factor '(-4 + -1b)' equal to zero and attempt to solve:

Simplifying
-4 + -1b = 0

Solving
-4 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -1b = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -1b = 0 + 4
-1b = 0 + 4

Combine like terms: 0 + 4 = 4
-1b = 4

Divide each side by '-1'.
b = -4

Simplifying
b = -4
Subproblem 2
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Solution
b = {-4, 2}