(b+4)/3=(b-8)/5

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Solution for (b+4)/3=(b-8)/5 equation: 



(b+4)/3=(b-8)/5

We move all terms to the left:

(b+4)/3-((b-8)/5)=0

We calculate fractions


b/()+(-((b-8)*3)/()=0



We calculate terms in parentheses: +(-((b-8)*3)/(), so:

-((b-8)*3)/(

We multiply all the terms by the denominator


-((b-8)*3)



We calculate terms in parentheses: -((b-8)*3), so:

(b-8)*3

We multiply parentheses

3b-24

Back to the equation:

-(3b-24)



We get rid of parentheses

-3b+24

Back to the equation:

+(-3b+24)



We get rid of parentheses

b/()-3b+24=0

We multiply all the terms by the denominator


b-3b*()+24*()=0

We add all the numbers together, and all the variables

b-3b*()=0

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