(b+5)(b-11)=

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Solution for (b+5)(b-11)= equation:


Simplifying
(b + 5)(b + -11) = 0

Reorder the terms:
(5 + b)(b + -11) = 0

Reorder the terms:
(5 + b)(-11 + b) = 0

Multiply (5 + b) * (-11 + b)
(5(-11 + b) + b(-11 + b)) = 0
((-11 * 5 + b * 5) + b(-11 + b)) = 0
((-55 + 5b) + b(-11 + b)) = 0
(-55 + 5b + (-11 * b + b * b)) = 0
(-55 + 5b + (-11b + b2)) = 0

Combine like terms: 5b + -11b = -6b
(-55 + -6b + b2) = 0

Solving
-55 + -6b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-5 + -1b)(11 + -1b) = 0

Subproblem 1

Set the factor '(-5 + -1b)' equal to zero and attempt to solve: Simplifying -5 + -1b = 0 Solving -5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1b = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1b = 0 + 5 -1b = 0 + 5 Combine like terms: 0 + 5 = 5 -1b = 5 Divide each side by '-1'. b = -5 Simplifying b = -5

Subproblem 2

Set the factor '(11 + -1b)' equal to zero and attempt to solve: Simplifying 11 + -1b = 0 Solving 11 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + -1b = 0 + -11 Combine like terms: 11 + -11 = 0 0 + -1b = 0 + -11 -1b = 0 + -11 Combine like terms: 0 + -11 = -11 -1b = -11 Divide each side by '-1'. b = 11 Simplifying b = 11

Solution

b = {-5, 11}

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