(b+5)(b-5)=0

Solution for (b+5)(b-5)=0 equation:

Simplifying
(b + 5)(b + -5) = 0

Reorder the terms:
(5 + b)(b + -5) = 0

Reorder the terms:
(5 + b)(-5 + b) = 0

Multiply (5 + b) * (-5 + b)
(5(-5 + b) + b(-5 + b)) = 0
((-5 * 5 + b * 5) + b(-5 + b)) = 0
((-25 + 5b) + b(-5 + b)) = 0
(-25 + 5b + (-5 * b + b * b)) = 0
(-25 + 5b + (-5b + b2)) = 0

Combine like terms: 5b + -5b = 0
(-25 + 0 + b2) = 0
(-25 + b2) = 0

Solving
-25 + b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + b2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + b2 = 0 + 25
b2 = 0 + 25

Combine like terms: 0 + 25 = 25
b2 = 25

Simplifying
b2 = 25

Take the square root of each side:
b = {-5, 5}