(b+6)(3b+8)=0

Solution for (b+6)(3b+8)=0 equation:

(b+6)(3b+8)=0

We multiply parentheses ..

(+3b^2+8b+18b+48)=0

We get rid of parentheses

3b^2+8b+18b+48=0

We add all the numbers together, and all the variables

3b^2+26b+48=0

a = 3; b = 26; c = +48;
Δ = b2-4ac
Δ = 262-4·3·48
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-10}{2*3}=\frac{-36}{6}
=-6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+10}{2*3}=\frac{-16}{6}
=-2+2/3
$