(b+6)/(b-3)=2

Solution for (b+6)/(b-3)=2 equation:

(b+6)/(b-3)=2

We move all terms to the left:

(b+6)/(b-3)-(2)=0


Domain of the equation: (b-3)!=0

We move all terms containing b to the left, all other terms to the right

b!=3

b∈R


We multiply all the terms by the denominator


(b+6)-2*(b-3)=0

We multiply parentheses

(b+6)-2b+6=0

We get rid of parentheses

b-2b+6+6=0

We add all the numbers together, and all the variables

-1b+12=0

We move all terms containing b to the left, all other terms to the right

-b=-12

b=-12/-1

b=+12