(b+7)(b-12)=0

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Solution for (b+7)(b-12)=0 equation:


Simplifying
(b + 7)(b + -12) = 0

Reorder the terms:
(7 + b)(b + -12) = 0

Reorder the terms:
(7 + b)(-12 + b) = 0

Multiply (7 + b) * (-12 + b)
(7(-12 + b) + b(-12 + b)) = 0
((-12 * 7 + b * 7) + b(-12 + b)) = 0
((-84 + 7b) + b(-12 + b)) = 0
(-84 + 7b + (-12 * b + b * b)) = 0
(-84 + 7b + (-12b + b2)) = 0

Combine like terms: 7b + -12b = -5b
(-84 + -5b + b2) = 0

Solving
-84 + -5b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-7 + -1b)(12 + -1b) = 0

Subproblem 1

Set the factor '(-7 + -1b)' equal to zero and attempt to solve: Simplifying -7 + -1b = 0 Solving -7 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1b = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1b = 0 + 7 -1b = 0 + 7 Combine like terms: 0 + 7 = 7 -1b = 7 Divide each side by '-1'. b = -7 Simplifying b = -7

Subproblem 2

Set the factor '(12 + -1b)' equal to zero and attempt to solve: Simplifying 12 + -1b = 0 Solving 12 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1b = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1b = 0 + -12 -1b = 0 + -12 Combine like terms: 0 + -12 = -12 -1b = -12 Divide each side by '-1'. b = 12 Simplifying b = 12

Solution

b = {-7, 12}

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