(b+8)/3=(b-5)/4

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Solution for (b+8)/3=(b-5)/4 equation: 



(b+8)/3=(b-5)/4

We move all terms to the left:

(b+8)/3-((b-5)/4)=0

We calculate fractions


b/()+(-((b-5)*3)/()=0



We calculate terms in parentheses: +(-((b-5)*3)/(), so:

-((b-5)*3)/(

We multiply all the terms by the denominator


-((b-5)*3)



We calculate terms in parentheses: -((b-5)*3), so:

(b-5)*3

We multiply parentheses

3b-15

Back to the equation:

-(3b-15)



We get rid of parentheses

-3b+15

Back to the equation:

+(-3b+15)



We get rid of parentheses

b/()-3b+15=0

We multiply all the terms by the denominator


b-3b*()+15*()=0

We add all the numbers together, and all the variables

b-3b*()=0

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