(b+9)/3+5=28

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Solution for (b+9)/3+5=28 equation: 



(b+9)/3+5=28

We move all terms to the left:

(b+9)/3+5-(28)=0

We add all the numbers together, and all the variables

(b+9)/3-23=0

We multiply all the terms by the denominator


(b+9)-23*3=0

We add all the numbers together, and all the variables

(b+9)-69=0

We get rid of parentheses

b+9-69=0

We add all the numbers together, and all the variables

b-60=0

We move all terms containing b to the left, all other terms to the right

b=60

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