(b+9)/5=b-2

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Solution for (b+9)/5=b-2 equation: 


b in (-oo:+oo)

(b+9)/5 = b-2 // - b-2

(b+9)/5-b+2 = 0

(b+9)/5+(5*(-b))/5+(2*5)/5 = 0

b+5*(-b)+2*5+9 = 0

9-4*b+10 = 0

19-4*b = 0

(19-4*b)/5 = 0

(19-4*b)/5 = 0 // * 5

19-4*b = 0

19-4*b = 0 // - 19

-4*b = -19 // : -4

b = -19/(-4)

b = 19/4

b = 19/4

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