(b-1)(b+1)=(b*b)

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Solution for (b-1)(b+1)=(b*b) equation: 



(b-1)(b+1)=(b*b)

We move all terms to the left:

(b-1)(b+1)-((b*b))=0

We add all the numbers together, and all the variables

(b-1)(b+1)-((+b*b))=0

We use the square of the difference formula

b^2-((+b*b))-1=0



We calculate terms in parentheses: -((+b*b)), so:

(+b*b)

We get rid of parentheses

b*b

Wy multiply elements

b^2

Back to the equation:

-(b^2)



We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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