(b-1)/6-(2b-1)/5b=0

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Solution for (b-1)/6-(2b-1)/5b=0 equation: 


b in (-oo:+oo)

(b-1)/6-(b*((2*b-1)/5)) = 0

(b-1)/6+(-1*b*(2*b-1))/5 = 0

(5*(b-1))/(5*6)+(-1*6*b*(2*b-1))/(5*6) = 0

5*(b-1)-1*6*b*(2*b-1) = 0

11*b-12*b^2-5 = 0

11*b-12*b^2-5 = 0

11*b-12*b^2-5 = 0

DELTA = 11^2-(-12*(-5)*4)

DELTA = -119

DELTA < 0

1 = 0

1/(5*6) = 0

1/(5*6) = 0 // * 5*6

1 = 0

b belongs to the empty set

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