(b-1/5)2=-23/25

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Solution for (b-1/5)2=-23/25 equation: 


b in (-oo:+oo)

(b-(1/5))^2 = -23/25 // + -23/25

(b-(1/5))^2-(-23/25) = 0

(b-1/5)^2+23/25 = 0

(25*(b-1/5)^2)/25+23/25 = 0

25*(b-1/5)^2+23 = 0

25*b^2-10*b+24 = 0

25*b^2-10*b+24 = 0

25*b^2-10*b+24 = 0

DELTA = (-10)^2-(4*24*25)

DELTA = -2300

DELTA < 0

1 = 0

1/25 = 0

1/25 = 0 // * 25

1 = 0

1 = 0

b belongs to the empty set

b belongs to the empty set

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