(b-2)+2b-(b-3)=11

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Solution for (b-2)+2b-(b-3)=11 equation:


Simplifying
(b + -2) + 2b + -1(b + -3) = 11

Reorder the terms:
(-2 + b) + 2b + -1(b + -3) = 11

Remove parenthesis around (-2 + b)
-2 + b + 2b + -1(b + -3) = 11

Reorder the terms:
-2 + b + 2b + -1(-3 + b) = 11
-2 + b + 2b + (-3 * -1 + b * -1) = 11
-2 + b + 2b + (3 + -1b) = 11

Reorder the terms:
-2 + 3 + b + 2b + -1b = 11

Combine like terms: -2 + 3 = 1
1 + b + 2b + -1b = 11

Combine like terms: b + 2b = 3b
1 + 3b + -1b = 11

Combine like terms: 3b + -1b = 2b
1 + 2b = 11

Solving
1 + 2b = 11

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2b = 11 + -1

Combine like terms: 1 + -1 = 0
0 + 2b = 11 + -1
2b = 11 + -1

Combine like terms: 11 + -1 = 10
2b = 10

Divide each side by '2'.
b = 5

Simplifying
b = 5

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