(b-25)(b+16)=0

Solution for (b-25)(b+16)=0 equation:

Simplifying
(b + -25)(b + 16) = 0

Reorder the terms:
(-25 + b)(b + 16) = 0

Reorder the terms:
(-25 + b)(16 + b) = 0

Multiply (-25 + b) * (16 + b)
(-25(16 + b) + b(16 + b)) = 0
((16 * -25 + b * -25) + b(16 + b)) = 0
((-400 + -25b) + b(16 + b)) = 0
(-400 + -25b + (16 * b + b * b)) = 0
(-400 + -25b + (16b + b2)) = 0

Combine like terms: -25b + 16b = -9b
(-400 + -9b + b2) = 0

Solving
-400 + -9b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-16 + -1b)(25 + -1b) = 0

Subproblem 1
Set the factor '(-16 + -1b)' equal to zero and attempt to solve:

Simplifying
-16 + -1b = 0

Solving
-16 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + -1b = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -1b = 0 + 16
-1b = 0 + 16

Combine like terms: 0 + 16 = 16
-1b = 16

Divide each side by '-1'.
b = -16

Simplifying
b = -16
Subproblem 2
Set the factor '(25 + -1b)' equal to zero and attempt to solve:

Simplifying
25 + -1b = 0

Solving
25 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-25' to each side of the equation.
25 + -25 + -1b = 0 + -25

Combine like terms: 25 + -25 = 0
0 + -1b = 0 + -25
-1b = 0 + -25

Combine like terms: 0 + -25 = -25
-1b = -25

Divide each side by '-1'.
b = 25

Simplifying
b = 25
Solution
b = {-16, 25}