(b-3)(b+1)=0

Solution for (b-3)(b+1)=0 equation:

Simplifying
(b + -3)(b + 1) = 0

Reorder the terms:
(-3 + b)(b + 1) = 0

Reorder the terms:
(-3 + b)(1 + b) = 0

Multiply (-3 + b) * (1 + b)
(-3(1 + b) + b(1 + b)) = 0
((1 * -3 + b * -3) + b(1 + b)) = 0
((-3 + -3b) + b(1 + b)) = 0
(-3 + -3b + (1 * b + b * b)) = 0
(-3 + -3b + (1b + b2)) = 0

Combine like terms: -3b + 1b = -2b
(-3 + -2b + b2) = 0

Solving
-3 + -2b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-1 + -1b)(3 + -1b) = 0

Subproblem 1
Set the factor '(-1 + -1b)' equal to zero and attempt to solve:

Simplifying
-1 + -1b = 0

Solving
-1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1b = 0 + 1
-1b = 0 + 1

Combine like terms: 0 + 1 = 1
-1b = 1

Divide each side by '-1'.
b = -1

Simplifying
b = -1
Subproblem 2
Set the factor '(3 + -1b)' equal to zero and attempt to solve:

Simplifying
3 + -1b = 0

Solving
3 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = 0 + -3
-1b = 0 + -3

Combine like terms: 0 + -3 = -3
-1b = -3

Divide each side by '-1'.
b = 3

Simplifying
b = 3
Solution
b = {-1, 3}