(b-3)*(b+2)=

Solution for (b-3)*(b+2)= equation:

Simplifying
(b + -3)(b + 2) = 0

Reorder the terms:
(-3 + b)(b + 2) = 0

Reorder the terms:
(-3 + b)(2 + b) = 0

Multiply (-3 + b) * (2 + b)
(-3(2 + b) + b(2 + b)) = 0
((2 * -3 + b * -3) + b(2 + b)) = 0
((-6 + -3b) + b(2 + b)) = 0
(-6 + -3b + (2 * b + b * b)) = 0
(-6 + -3b + (2b + b2)) = 0

Combine like terms: -3b + 2b = -1b
(-6 + -1b + b2) = 0

Solving
-6 + -1b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-2 + -1b)(3 + -1b) = 0

Subproblem 1
Set the factor '(-2 + -1b)' equal to zero and attempt to solve:

Simplifying
-2 + -1b = 0

Solving
-2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1b = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1b = 0 + 2
-1b = 0 + 2

Combine like terms: 0 + 2 = 2
-1b = 2

Divide each side by '-1'.
b = -2

Simplifying
b = -2
Subproblem 2
Set the factor '(3 + -1b)' equal to zero and attempt to solve:

Simplifying
3 + -1b = 0

Solving
3 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = 0 + -3
-1b = 0 + -3

Combine like terms: 0 + -3 = -3
-1b = -3

Divide each side by '-1'.
b = 3

Simplifying
b = 3
Solution
b = {-2, 3}