(b-3)+6=2

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Solution for (b-3)+6=2 equation: 



(b-3)+6=2

We move all terms to the left:

(b-3)+6-(2)=0

We add all the numbers together, and all the variables

(b-3)+4=0

We get rid of parentheses

b-3+4=0

We add all the numbers together, and all the variables

b+1=0

We move all terms containing b to the left, all other terms to the right

b=-1

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