(b-3)-(b+8)=9b

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Solution for (b-3)-(b+8)=9b equation: 



(b-3)-(b+8)=9b

We move all terms to the left:

(b-3)-(b+8)-(9b)=0

We add all the numbers together, and all the variables

-9b+(b-3)-(b+8)=0

We get rid of parentheses

-9b+b-b-3-8=0

We add all the numbers together, and all the variables

-9b-11=0

We move all terms containing b to the left, all other terms to the right

-9b=11

b=11/-9

b=-1+2/9

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