(b-3)=(b+2)

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Solution for (b-3)=(b+2) equation: 



(b-3)=(b+2)

We move all terms to the left:

(b-3)-((b+2))=0

We get rid of parentheses

b-((b+2))-3=0



We calculate terms in parentheses: -((b+2)), so:

(b+2)

We get rid of parentheses

b+2

Back to the equation:

-(b+2)



We get rid of parentheses

b-b-2-3=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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