(b-4)(b-2)=0

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Solution for (b-4)(b-2)=0 equation:


Simplifying
(b + -4)(b + -2) = 0

Reorder the terms:
(-4 + b)(b + -2) = 0

Reorder the terms:
(-4 + b)(-2 + b) = 0

Multiply (-4 + b) * (-2 + b)
(-4(-2 + b) + b(-2 + b)) = 0
((-2 * -4 + b * -4) + b(-2 + b)) = 0
((8 + -4b) + b(-2 + b)) = 0
(8 + -4b + (-2 * b + b * b)) = 0
(8 + -4b + (-2b + b2)) = 0

Combine like terms: -4b + -2b = -6b
(8 + -6b + b2) = 0

Solving
8 + -6b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2 + -1b)(4 + -1b) = 0

Subproblem 1

Set the factor '(2 + -1b)' equal to zero and attempt to solve: Simplifying 2 + -1b = 0 Solving 2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b = 0 + -2 -1b = 0 + -2 Combine like terms: 0 + -2 = -2 -1b = -2 Divide each side by '-1'. b = 2 Simplifying b = 2

Subproblem 2

Set the factor '(4 + -1b)' equal to zero and attempt to solve: Simplifying 4 + -1b = 0 Solving 4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1b = 0 + -4 -1b = 0 + -4 Combine like terms: 0 + -4 = -4 -1b = -4 Divide each side by '-1'. b = 4 Simplifying b = 4

Solution

b = {2, 4}

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